In each of the following experiments specify appropriate sample space A boy has a $1$ rupee coin, a $2$ rupee coin and a $5$ rupee coin in his pocket. He takes out two coins out of his pocket, one after the other.
Let $Q$ denote a $1$ rupee coin, $H$ denotes a $2$ rupee coin and $R$ denotes a $5$ rupee coin. The first coin he takes out of his pocket may be any one of the three coins $Q$, $H$ or $R$. Corresponding to $Q$. the second draw may be $H$ or $R$. So the result of two draws may be $QH$ or $QR$. Similarly, corresponding to $H$, the second draw may be $Q$ or $R$.
Therefore, the outcomes may be $HQ$ or $HR$. Lastly, corresponding to $R$, the second draw may be $H$ or $Q$.
So, the outcomes may be $RH$ or $RQ$.
Thus, the sample space is $S =\{ QH ,\, QR ,\, HQ , \,HR , \,RH ,\, RQ \}$
If $P(A) = 0.65,\,\,P(B) = 0.15,$ then $P(\bar A) + P(\bar B) = $
Let $\Omega$ be the sample space and $A \subseteq \Omega$ be an event. Given below are two statements :
$(S1)$ : If $P ( A )=0$, then $A =\phi$
$( S 2)$ : If $P ( A )=$, then $A =\Omega$
Then
Two cards are drawn from a pack of $52$ cards. What is the probability that one of them is a queen and the other is an ace
A locker can be opened by dialing a fixed three digit code (between $000$ and $999$). A stranger who does not know the code tries to open the locker by dialing three digits at random. The probability that the stranger succeeds at the ${k^{th}}$ trial is
For the two events $A$ and $B$, $P(A) = 0.38,\,$ $P(B) = 0.41,$ then the value of $P(A$ not) is